An Introduction to Mechanical Engineering: Part 2 by Michael Clifford

By Michael Clifford

An creation to Mechanical Engineering: half 2 is a vital textual content for all second-year undergraduate scholars in addition to these learning starting place levels and HNDs. The textual content offers thorough insurance of the subsequent middle engineering topics:

  1. Fluid dynamics
  2. Thermodynamics
  3. Solid mechanics
  4. Control concept and techniques
  5. Mechanical strength, so much and transmissions
  6. Structural vibration

As good as mechanical engineers, the textual content can be hugely appropriate to automobile, aeronautical/aerospace and basic engineering students.

The fabric during this ebook has complete pupil and lecturer aid on an accompanying web site at, which includes:

  • worked ideas for exam-style questions
  • multiple-choice self-assessment
  • revision material

The textual content is written by means of an skilled workforce of academics on the the world over popular collage of Nottingham.

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Extra resources for An Introduction to Mechanical Engineering: Part 2

Sample text

The law of conservation of energy states that energy can be neither created nor destroyed but only transformed from one type to another, and this is the essence of the first law of thermodynamics met in Part 1, and henceforward referred to as ‘the first law’. Heat and work are forms of energy; they have the same units as energy. The laws of thermodynamics consider the relationship between heat and work and the effect that the transfer has on the energy of the matter that undergoes the transfer.

3) By what percentage does the drag force change if the flow becomes laminar rather than turbulent? (4) Explain the behaviour of the fork ball as described above using the principles of fluid mechanics. (5) Discuss how the pitcher should adjust the delivery of the fork ball for it to remain effective if the ball surface becomes rough during a game. 5. 5 times (150% increase). (4) The fork ball is the result of reverse transition (from turbulent to laminar rather than usual laminar to turbulent route) of flow around the ball.

We can easily see that these two cannot form a non-dimensional quantity.  Since the p theorem After some calculation, we find that p1 5 ____ Q n D2 cannot give a functional form of a non-dimensional quantity, we take the liberty of Q nD3 ​. making an assumption on its form. Conventionally, we use ​ ____ 3 ​ rather then ​ ____ nD Q Therefore, we set Q 1 ​ ​ 5 ​ ____ 3 ​ p195 ___ p1 nD The performance of the centrifugal pump can be expressed as p2 5 fn (p19): ( nD ) gH Q _____ ​ 5 fn​ ____ ​ 3 ​ ​ ​ 2 n D2 or, CH 5 fn(CQ) where, CH and CQ are the head coefficient and the capacity coefficient, respectively.

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